Help plz plz will mark brainliest

x = 52°

Acute angle = 64°

Step-by-step explanation:

Problem 1:

Since DN bisects <BDW, this means that m<BDN = m<NDW

Thus:

5v - 8 = 4v + 4

Collect like terms

5v - 4v = 8 + 4

v = 12

x = m<BDN = 5v - 8

x = 5v - 8

Plug in the value of v

x = 5(12) - 8

x = 52°

Problem 2:

First, find the value of y

(4y - 44) + (3y + 35) = 180 (linear pair)

4y - 44 + 3y + 35 = 180

7y - 9 = 180

7y = 180 + 9

7y = 189

Divide both sides by 7

y = 27

Acute angle = 4y - 44

Plug in the value of y

Acute angle = 4(27) - 44 = 64°

8

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)