Given that z is a standard normal random variable, find the value of z for each situation. a. The area to the right of z is 0.01.

=1.34

Step-by-step explanation:

In standard density curve

P(Z<z) = Area left of z, P(Z>z) = area right of z.

P(Z<z) +P(Z>z) =1

Given:  z is a standard normal random variable.

To find : value of z if rea to the right of z is 0.01.

i.e. P(Z>z) =0.01

P(Z<z) =1-0.01 = 0.09

from z-score table, z value for this is 1.34.

Hence, z= 1.34

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