The measures of two sides of a triangle are 8 and 15, what is the range possible values for the third side?

The required range is .

Step-by-step explanation:

Consider the provided information.

Let the side A = 15 and the side B = 8

Theorem 1: For a triangle with sides A, B, and C the sum of the lengths of any two sides of a triangle must be greater than the third side:

....(1)

 ...(2)

 ....(3)

By using equations 1 and 2.

Therefore,

Hence, the required range is .

42

step-by-step explanation:

256/6=42

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!