Find the volume of cube whose dimensions are (x+7y),(7x-y) and (xy-5)

7x³y - 35x² + 35y² + 48x²y² - 240xy - 7xy³

Step-by-step explanation:

Dimensions of the cube = (x+7y),(7x-y) and (xy-5)

Volume of the cube = (x+7y) (7x-y) (xy-5)

= (7x² - xy + 49xy - 7y²)(xy - 5)

= 7x³y - 35x² - x²y² + 5xy + 49x²y² - 245xy - 7xy³ + 35y²

= 7x³y - 35x² + 35y² + 49x²y² - x²y² + 5xy - 245xy - 7xy³

= 7x³y - 35x² + 35y² + 48x²y² - 240xy - 7xy³

Volume of the cube = 7x³y - 35x² + 35y² + 48x²y² - 240xy - 7xy³

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step-by-step explanation:

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: