A polygon is shown: A polygon MNOPQR is shown. The top vertex on the left is labeled M, and rest of the vertices are labeled clockwise starting from the top left vertex labeled, M. The side MN is parallel to side QR. The side MR is parallel to side PQ. The side MN is labeled as 2 units. The side QR is labeled as 9 units. The side MR is labeled as 3 units, and the side NO is labeled as 2 units.

The area of polygon MNOPQR = Area of a rectangle that is 6 square units + Area of a rectangle that is ___ square units. (Input only whole numbers, such as 8.)

Numerical Answers Expected!

Answer for Blank 1:

answer: ♡♡♡♡♡♡♡♡♡♡

step-by-step explanation:

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

your answer is  

a.

5

step-by-step explanation: