You are going to an amusement park over Spring Break. The cost of admission to enter the park is $30 and the rides are an additional $6 each. If your parents give you $100 to spend at the amusement park, what is the maximum number of rides you can go on? Write an inequality to show the maximum number of rides you can go on.

30+6x ≤ 100 (inequality)

The maximum amount of rides is 11 rides

Step-by-step explanation:

So first the admission fee is 30

Each ride is 6

So since you can go on any amount of rides, its unknown so (x)

You only have a 100 dollars and you can’t go over but you can go lower

so 30+6x≤100

If you solve it

x≤11

So 11 rides

30+6x=100

Step-by-step explanation:

100-30=70

6*11= 66

The total number of rides he can go on is 11. He will have a remaining balance of $4.00 which is not enough to pay for another ride.

fsfd

step-by-step explanation:

fdddff

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer