What is the midpoint of the segment shown below? 10.
(-3,4)
O A. (-3.3)
O B. (-9,3)
- (-6,-1)
10
C. (- )
D. (-9,3)

Need help please

(-9/2,3/2)

Step-by-step explanation:

x coordinate of mid point=(x1+x2)/2

y coordinate of mid point=(y1+y2)/2

correct answer:

b.(19,-2)

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.