Your given two side lengths of 6 centimeters and 9 centimeters. Which measurement can you use for the length of the third side to construct a valid triangle

3cm < L < 15cm

Step-by-step explanation:

Given :

Side lengths:

Side 1 = 6cm and side 2 = 9cm

In other to construct a valid triangle, the length of the third side must lie in between.

That is ;

Minimum length must be greater than :

(side 2 - side 1)

9cm - 6cm = 3cm

Maximum length must not exceed :

(side 1 + side 2)

9cm + 6cm = 15cm

Hence, for a valid length for the 3rd side, L:

L > 3cm and L < 15 cm

3cm < L < 15cm

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: