Urgent: In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving AEC ≅ DEB, given that CA is parallel to DB and E is the midpoint of AD. Submit the entire proof to your instructor.

Given:

CA || DB

E is the midpoint of AD

Prove:

AEC ≅ DEB

AEC and DEB wouldn't be the same size because they never said that CA and DB are the same length. Therefore, it could change up the whole thing.

Step-by-step explanation:

If AC and DB were the same length, then AEC≅DEB (In Image attached. figure 1 )

BUT since you don't know that, you can't assume that they are and they would end up looking like Figure 2

So in the end, if AC and DB are the same length, then AEC ≅ DEB but if they are not, then AEC is not ≅ to DEB

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

step-by-step explanation:

to find if any function is an inverse of the other, put the first equation in as x in the next one. then simplify and solve. if at the end you get the statement y = x, then it is an inverse. if you get anything else, it is not.