You have 42 coins valued at $6.00. Some of the coins some are quartersFind the number you have of each. Set up and solve a system of equations needed to solve the problem.

Complete Question

Mark has 42 coins consisting of dimes and quarters. the total value of his coins is $6. How many of each type of coin does he have?

The number of dimes = d = 30 dimes

The number of quarters = q = 12 quarters

Step-by-step explanation:

Let us represent

The number of dimes = d

The number of quarters = q

A dime is worth 10 cents = 0.10d

A quarter is worth 25 cents = 0.25q

Mark has 42 coins consisting of dimes and quarters.

q + d = 42 Equation 1

q = 42 - d

The total value of his coins is $6.

0.1d + 0.25q = 6

We substitute 42 - d for q

0.1d + 0.25(42 - d) = 6

0.1d + 10.5 - 0.25d = 6

10.5 - 6 = 0.25d - 0.1d

4.5 = 0.15d

d = 4.5/0.15

d = 30 dimes

Solving for q

q = 42 - d

q = 42 - 30

q = 12 dimes

Therefore,

The number of dimes = d = 30 dimes

The number of quarters = q = 12 quarters

0.5?

hope your goes well, here's a turkey

-thekoolkid1o1

the answer is c.

perimeters = 3√10/5

areas = 90/25

i got it down chief.