प्रत्येक पिलरको आधार 6 फिट x 6 फिट छ । उक्त पिरामिडसहितको पिलरहरूमा प्रति वर्ग फिट रु. 80 का दरले
छन्।
रङ्ग
लगाउँदा जम्मा कति खर्च लाग्छ ?
Two pillars of height 8 feet each with four faces
shown, of the gate of a stadium have one-one
pyramid of height 4 feet each having the same base
on their tops. The base of each pillar is 6 ft x 6 ft. If
the pillars with pyramid are painted at the rate of
Rs 80 per square feet, what will be the total cost?
23. एउटा आयताकार जग्गाको क्षेत्रफल 500 वर्ग मिटर र परिमिति
90 मिटर छ । उक्त जग्गालाई वर्गाकार बनाउन लम्बाइ अथवा
चौडाइलाई कति प्रतिशतले घटाउनु पर्छ र किन ?

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

the answer is 1030 it's very simple math.