Find the center and radius of this circle x^2+y^2-6x-10y+30=0

The circle's centre is at the position (3, 5), and it has a radius of 2

Step-by-step explanation:

First let's put it in a useful format by completing the squares:

x² + y² - 6x - 10y + 30 = 0

x² - 6x + y² - 10y = -30

x² - 6x + 9 + y² - 10y + 25 = -30 + 9 + 25

(x - 3)² + (y - 5)² = 4

This tells us that the centre position is (3, 5) and the radius is √4, or 2

r and t.

both are 64 degrees.