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Answer

y=5x−10.

Explanation:

The slope of a line passing through the two points P=(x1,y1) and Q=(x2,y2) is given by m=y2−y1x2−x1.

We have that x1=3, y1=5, x2=2, y2=0.

Plug the given values into the formula for slope: m=(0)−(5)(2)−(3)=−5−1=5.

Now, the y-intercept is b=y1−m⋅x1 (or b=y2−m⋅x2, the result is the same).

b=5−(5)⋅(3)=−10.

Finally, the equation of the line can be written in the form y=mx+b.

y=5x−10.

The slope of the line is m=5.

The equation of the line in the slope-intercept form is y=5x−10.

The equation of the line in the point-slope form is y−5=5(x−3).

The equation of the line in the point-slope form is y=5(x−2).

The general equation of the line is 5x−y−10=0.

300pi

step-by-step explanation:

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