A skier is on the top of a 350 meter tall mountain looking down at a tree. The direct path from the tree to the skier is 505 meters. What is the angle of depression from where the skier is standing to the base of the tree

Step-by-step explanation:

We are given that

Height of mountain=350 m

Distance  from the tree to the skier=505 m

We have to find the angle of depression from where the skier is standing to the base of the tree.

In triangle ABC

By using the formula

Hence, the angle of depression from where the skier is standing to the base of the tree=

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.