HELPP ASAP on a windy winters day the actual air temps turn is -5C and the wind speed is 15 kilometers per hour. What would the wind chill factor make the temperature feel like to a person outdoors? A. 1.7C
B. -5C
C. -10.6 C
D. -16.7 C

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

a: inscribed angles

step-by-step explanation:

i reviewed this question with a peer and teacher, seems to be correct, me later