Carson's tablet has 2,000 videos. The play time for the videos is skewed to the right, with a mean of 135 seconds and a standard deviation of 25 seconds. Part A: Can you accurately calculate the probability that the mean play time is more than 142 seconds for an SRS of 10 videos? Explain. (4 points)

Part B: If you take a random sample of 50 videos instead of 10, explain how the Central Limit Theorem allows you to find the probability that the mean play time is more than 142 seconds. Calculate this probability and show your work. (6 points)

SEE BELOW

Step-by-step explanation:

A: Yes, it is 18.80%. Sample Mean= 135, Sample Standard deviation= 25/sq rt of 10 = 7.906, normalcdf(142, 999999, 135, 7.906) = .18796 × 100 = 18.796 = 18.80%

B: If we increase the sample size to 50, then, due to the Central Limit Therme, there should be less variation within the data (it should point to a more clear center). Sample Mean= 135, Sample Standard deviation= 25/sq rt of 50 = 3.535, normalcdf(142, 999999, 135, 3.535) = .02385 × 100 = 2.385 = 2.39%

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse