Hannaford sells two sizes of cheerios cereal. The smaller box contains 9 ounces and costs $2.50. The larger box contains 20 ounces and and costs 3.79. What is the
difference in cost in dollars per ounce between the two sizes?

Quantity of cheerios cereal in the smaller box Hannaford sold = 9 ounces

Cost of nine ounces of cheerios cereal = $2.50

Cost of one ounce of cheerios cereal :

Cost of one ounce of cheerios cereal in the smaller box = $0.27

Quantity of cheerios cereal in the larger box Hannaford sold = 20 ounces

Cost of nine ounces of cheerios cereal = $3.79

Cost of one ounce of cheerios cereal :

Cost of one ounce of cheerios cereal in the larger box = $0.18

Difference in their cost per ounce :

Therefore, the difference in cost in dollars per ounce between the two sizes = $0.09

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.