Find the coordinates of the point on the directed segment from (1,2) to (6,12) that divides it into a ratio of 2:3

Point of contact  ( 3,6)

Step-by-step explanation:

Step(i):-

Given that the points are (1,2) and (6,12)

The ratio 2:3 divides the line segment

The line segment divides m:n externally

Step(ii):-

(x₁, y₁) = (1,2) and (x₂, y₂)= (6,12) and m:n =2:3

(

(

(3 , 6)

Final -

Point of contact  ( 3,6)

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

the answer is d

step-by-step explanation: