A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Use equation, find the maximum height reached by the rocket, to the nearest 10th of a foot . Y=-16x^2+261x+130

Maximum height of the rocket = 1194.39 feet.

Step-by-step explanation:

The equation that shows the height of the rocket, y in feet, is related to the time after launch, x in seconds is as follows :

...(1)

We need to find the maximum height reached by rocket. For maximum height,

Put x = 8.15 s in equation (1).

So, the maximum height of the rocket is 1194.39 feet.

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?