Two straight lines have equations y = p x + 4 y = p x + 4 and p y = q x − 7 p y = q x − 7 , where p p and q q are constants. The two lines meet at the point ( 3 , 1 ) ( 3 , 1 ) . What is the value of q q ?

q =

Step-by-step explanation:

The point of intersection (3, 1 ) is the solution to both equations

Using

y = qx - 7 and substituting x = 3, y = 1

1 = 3q - 7 ( add 7 to both sides )

8 = 3q ( divide both sides by 3 )

= q

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =