A particle moves along a line so that its position at any time t > 0 is given by the function s(t) = - t3 + 7t2 - 14t +8 where s is measured in meters and t is measured in seconds. Find the displacement during the first 5 seconds.

s(5) = -12

Step-by-step explanation:

s(t) = - t³ + 7t² - 14t +8

Find the displacement during the first 5 seconds.

When t = 5

s(t) = - t³ + 7t² - 14t +8

s(5) = -5³ + 7(5)² - 14(5) + 8

= -125 + 7(25) - 70 + 8

= -125 + 175 - 70 + 8

= -12

s(5) = -12

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

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.

(

−

∞

,

−

2

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∪

[

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{

y

|

y

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step-by-step explanation:

include a picture of the drawing in order for me to

step-by-step explanation: