Two planes leave an airport at the same time, one flying east, the other flying west. The eastbound plane travels 130 mph slower. They are 3850 mi apart after 5 hr. Find the speed of each plane.

Speed of the slower plane = 320 mph

Speed of the faster plane = 450 mph

Step-by-step explanation:

Let the speed of the slower plane = x mph

And the speed of the faster plane = y mph

Difference in their speeds = 130 mph

y - x = 130 (1)

Formula for the distance traveled = Speed × time

Distance traveled by the faster plane in 5 hours = 5y miles

Distance traveled by the slower plane in 5 hours = 5x miles

Total distance traveled by both the planes in 5 hours = 5(x + y) miles

5(x + y) = 3850

x + y = 770 (2)

By adding equations (1) and (2)

2y = 900

y = 450 mph

From equation (2)

x = 770 - 450

x = 320 mph

answer: i guess 5 units?

step-by-step explanation: