ABCD is a parallelogram, find x+ y

Step-by-step explanation:

Here, ABCD is a parallelogram.

∠CBD=40

o

 and ∠BAD=80

o

.

AD∥BC and BD is a transversal.

∴  ∠ADB=∠CBD            [ Alternate angles ]

∴  ∠ADB=40

o

.

∴  y=40

o

.

In △ADB,

⇒  ∠ADB+∠DBA+∠BAD=180

o

⇒  40

o

+x+80

o

=180

o

⇒  120

o

+x=180

o

⇒  x=180

o

−120

o

⇒  x=60

o

We get, x=60

o

 and y=40

o

.