Given: y = 12 when x = 7, find: “y” when x = 5.

y = 84/5 or 16 4/5

Step-by-step explanation:

12/5 = y/7

cross-multiply to get 5y = 84

y = 84/5

26

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb