Build a a table of estimates for f'(2): compute a one-sided difference quotient with the adjacent point for the first and last value, and an average of two difference quotients with adjacent points for
all other values.
Round all values to 2 decimal(s).
2
0
2
4
6
8
f'(2)

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

there is no question content here, but you for the free points! : d

dont know

step-by-step explanation: