Which 01 the following options best describes the zeros of the quadratic function above? 0) Imaginary zeros
() 2 real zeros
1 real zero and 1 Imaginary zero
f 1 real zero

Option (1)

Step-by-step explanation:

Vertex form of the quadratic equation is given by,

y = (x - h)² + k

Where (h, k) is the vertex.

From the graph attached,

Vertex of the parabola is (0, 4).

Therefore, equation of the parabola will be,

y = (x - 0)² + 4

y = x² + 4

Function representing the parabola will be,

f(x) = x² + 4

For the zeros of the quadratic function we find the value of x where f(x) = 0.

x² + 4 = 0

x² = -4

x = ±√(-4)

Since, square root of a negative number is not defined, zeros of the function will be imaginary.

Therefore, both the zeros will be imaginary.

It's clear from the graph, there are no x intercepts of the function Or zeros are imaginary.

Option (1) will be the answer.

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3