Mathematics, 08.02.2021 17:30 pearfam98

Geometry A. In unit 2, you learned three different criteria for proving triangle congruence: ASA, SAS, and SSS. Can you give me the summarize each of them for me? 100 POINTS

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Answer from: anonymous9723

we use the ASA when a triangle is conguerent by angle,side,angle.

SAS se when atriangle is conguerent by side,angle,side

sss when the triangle is conguerent by side,side,side

Answer from: hwilson118027

ASA- The Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.

SAS- is a rule used to prove whether a given set of triangles are congruent. The SAS rule states that: If two sides and the included angle of one triangle are equal to two sides and included angle of another triangle, then the triangles are congruent.

SSS- If two triangles are congruent it means that all corresponding angle pairs and all corresponding sides are congruent. The SSS criterion for triangle congruence states that if two triangles have three pairs of congruent sides, then the triangles are congruent

Step-by-step explanation:

Answer from: Quest

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

Which statement is not true about the data shown by the box plot below?

Answer from: Quest

$w\geq 14$

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

$2l+2w\geq 40$

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

$2\times 6+2w\geq 40$

now, we can solve for w

$12+2w\geq 40$

subtract both sides by 12

$12+2w-12\geq 40-12$

$2w\geq 28$

divide both sides by 2

and we get

$w\geq 14$

so,

the smallest possible measurement of the width is 14 feet

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