The area of a regular hexagon inscribed in a circle with radius 2 is . Round your answer to the nearest tenth.

10.4 to nearest tenth.

Step-by-step explanation:

If we draw lines from the centre of the circle to each vertex of the hexagon we get 6  equilateral triangles  of side length 2.

Altitude of each triangle  = sqrt(2^2 - 1^2)

= sqrt3.

So the area of 1 triangle = 1/2 * 2 * sqrt3

= sqrt3

Therefore the area of the hexagon = 6 * sqrt3

= 6sqrt3

= 10.3923

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step-by-step explanation:

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