A person invest $3000 in a bank the bank pays 6.75% interest compounded semi annually to the nearest 10th of a year how long must a person leave the money in the bank until it reaches $6700

It would take 12.1 years.

Step-by-step explanation:

We are given with $3000 invested in bank pays 6.75% interest compounded semi annually to the nearest 10th. We are asked to find the number of years the bank reaches $6700.

Let's use the compound interest formula.

We know A=6700

P=3000

r =0.0675

n=2(because compounded semiannually)

t =?( we need to find it)

Plug in the known values into the formula.

Simplify and solve for 't'

Divide both sides by 3000

Take log on both sides

Divide both sides by log(1.03375)

24.2067=2t

Divide both sides by 2.

t=12.10...

To round to nearest 10th, we get t=12.1 years.

its 4 because 2 times 2 is 4, if you double the number two you get four

b

step-by-step explanation: