Aclass of 40 students has 11 honor students and 10 athletes. three of the honor students are also athletes. one student is chosen at random. find the probability that this student is an athlete if it is known that the student is not an honor student. round to the nearest thousandth.

The correct answer is:

7/29 = 0.24.

Explanation:

We can construct a two-way table from this information.

There are 40 total students. 10 of them are athletes; this means 40-10 = 30 are not athletes.

3 of the athletes are honors students. There are 10 athletes; this means there are 10-3 = 7 athletes that are not honors students.

There are 11 honors students. This means that there are 40-11 = 29 students that are not honors students.

For this probability, we only consider the number of athletes that are not honors students (7) and the total number of students that are not honors students (29). This makes the probability 7/29 = 0.24.

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

my guess would be b and d, but i didn’t actually get out the pen and paper. lol