Find the Quadratice function with given vertex (5,8) and given point (1,3)

Given:

Consider the quadratic function is

With given vertex (5,8) and given point (1,3).

To find:

The equation of quadratic function.

Solution:

The quadratic function is

              ...(i)

Where, (h,k) is the vertex and a is a constant.

Vertex is (5,8). So,

Putting in (i), we get

          ...(ii)

The given point is (1,3). Putting x=1 and y=3 in  (ii), we get

Putting in (ii), we get

Therefore, the required quadratic function is .

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

well the answer to that is xoxoxo

step-by-step explanation: