Write the quadratic equation and solve by using the general formula. "Find two consecutive numbers in which the double of the square of the smaller number plus the square of the greater number is 121"

6 and 7

Step-by-step explanation:

Let the numbers be x and x + 1

We can form and equation as:

2(x²) + (x+1)² = 121

2x² + (x + 1)(x + 1) = 121

2x² + x² + x + x + 1 = 121

3x² + 2x = 121 - 1

3x² + 2x = 120

3x² + 2x - 120 = 0

3x² - 18x + 20x - 120 = 0

3x(x - 6) + 20(x - 6)

Therefore, x - 6 = 0

x = 0 + 6

x = 6

The numbers are 6 and 7

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

step-by-step explanation: