E16.15 Keynote Inc. uses a calendar year for financial reporting. The company is authorized to issue 20,000,000 shares of $1 par common stock. At no time has Keynote issued any potentially dilutive securities. Listed below is a summary of Keynote’s common stock activities. 1. Number of common shares issued and outstanding at December 31, 2018 5,000,000
2. Shares issued for cash on March 31, 2019 1,000,000
3. A 2-for-1 stock split of Keynote’s common stock took place on August 31, 2020.
4. Shares issued as a result of a 30% stock dividend on June 30, 2021 3,600,000

Instructions
(a) Compute the weighted-average number of common shares used in computing earnings per common share for 2019 on the 2020 comparative income statement.
(b) Compute the weighted-average number of common shares used in computing earnings per common share for 2020 on the 2020 comparative income statement.
(c) Compute the weighted-average number of common shares to be used in computing earnings per common share for 2020 on the 2021 comparative income statement.
(d) Compute the weighted-average number of common shares to be used in computing earnings per common share for 2021 on the 2021 comparative income statement. (CMA adapted)

the answer to question 1 is -8, 28.

step-by-step explanation:

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.

answer: i dont know but if you try hard you will get it right : )

step-by-step explanation: