One number is 1 less than a second number. Twice the second number is 25 less than 5 times the first. Find the two numbers. The smaller number is
The larger number is

9 and 10

Step-by-step explanation:

This problem calls for setting up a system of equations. Let's call the first number n and the second number s.

One number is 1 less than a second number (hint: 'is' typically means equals!):

Twice a second number is 25 less than 5 times the first.

Now that we have a system set up, we can use substitution to solve.

Substitute the 'n' variable in the second equation with the value that we gave it in the first equation.

Now that we have only one variable, we can solve algebraically!

Now that we have the value of one variable, we can go back to the original equations and plug in s in order to solve for n.

And there we have both numbers!

I hope this helps!

answer: the common difference is -0.10