. Given that r satisfies the inequality 20.x > 33, find the smallest value of x if .r is a prime number.​

x = 2.

Step-by-step explanation:

By an online search, i found that the question is:

"Given that x satisfies the inequality 20*x > 33,  find the smallest value of x if x is a prime number."

To find the smallest value of x we need to input different possible values of x (where we have the condition that x must be a prime number) and see which one is the first one that makes the inequality true.

The prime numbers are:

2, 3, 5,

Let's start with the smaller one, x = 2

So we input it in the inequality and get:

20*2 > 33

40 > 33

this is true.

Then we can have x = 2, which is the smaller prime number that satisfies the inequality.

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

50.6

step-by-step explanation: