Mathematics, 27.11.2019 02:31 yair7
Solve the equation 3tan(2x+15°)=4 for 0°is less than equal to x and 180° is greater than equal to x.
Answers: 1
![\large\begin{array}{l} \textsf{Take the inverse tangent function of both sides:}\\\\ \mathsf{2x+15^\circ=tan^{-1}\!\left(\dfrac{4}{3}\right)+k\cdot 180^\circ}\\\\ \mathsf{2x=tan^{-1}\!\left(\dfrac{4}{3}\right)-15^\circ+k\cdot 180^\circ}\\\\ \mathsf{x=\dfrac{1}{2}\cdot \left[tan^{-1}\!\left(\dfrac{4}{3}\right)-15^\circ+k\cdot 180^\circ \right]}\\\\ \mathsf{x=\dfrac{1}{2}\,tan^{-1}\!\left(\dfrac{4}{3}\right)-\dfrac{15^\circ}{2}+k\cdot \dfrac{180^\circ}{2}}\end{array}](/tpl/images/0392/6099/4457c.png)
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Solve the equation 3tan(2x+15°)=4 for 0°is less than equal to x and 180° is greater than equal to x....
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