≠A student took a system of equations, multiplied the first equation by and the second equation by , then added the results together. Based on this, she concluded that there were no solutions. Which system of equations could she have started with?

C. 3x+6y=9  and-2x-4y=4

Step-by-step explanation:

Given

Steps:

The attachment completes the question

(a): -2x+4y=4 and -3x+6y=6

Multiply by 2:

Multiply by 3:

Add together

B. 3x+y=12  and -3x+6y=6

Multiply by 2:

Multiply by 3:

Add together:

C. 3x+6y=9  and-2x-4y=4

Multiply by 2:

Multiply by 3:

Add together:

This is the equation the student could have used because 0 = 30 means the equation has no solution.

your answer is b ^w^ hope i

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐