What is an equation of the line that passes through the points (8,-1) and (4,-1)?pleaseee i need helppp

y = -1

Step-by-step explanation:

Put the equation in the form y = mx + b where m is the slope and b is the y-intercept.

First, find the slope by doing change in y / change in x:

-1 - (-1) / 8 - 4  = 0 / 4 = 0

this means that m = 0, so the equation so far is y = 0x + b or y = b

Then, you need to find what b is and since you know x = 8 and y = -1 is a solution, you can plug that into the equation:

-1 = 0 * 8 + b

-1 = b

This means that b = -1 and the equation would be y = -1

y=-1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-(-1))/(4-8)

m=(-1+1)/-4=0/-4=0

slope is 0

y-y1=m(x-x1)

y-(-1)=0(x-8)

y+1=0

y=0-1=-1

y=-1

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363