Find the x-intercept and and y-intercept algebraically y = log2 (x + 1) - 3

need work

x intercept is 7 y intercept is -3

Step-by-step explanation:

Write equation out and have y=0

Add 3 to both sides

Using the log to exponet rule

Where b and x are real numbers and b cannot equal 1.

Reorder the equation as a exponet

Simplify

Subtract 1 from both sides

So the x intercept is 7

To find y intercept plug 0 in as x

Add 3 to both sides

Rewrite in exponet form

Using the zero exponet property, anything to the zero power equal 1 so we must find a value that equal out to zero using the exponet so we'll set up the equation

Subtract 3 from both sides and we get

So the x intercept is 7 and the y intercept is -3