a cone has a height of 4 ft and a volume of 7.77 Ft cubed determine its radius to the nearest tenth of a foot​

The radius of the cone is approximately 1.4 feet

Step-by-step explanation:

The given parameters of the cone are;

The height of the cone, h = 4 ft.

The volume of the cone, V = 7.77 ft.³

The volume, 'V', of a cone is given by the following formula;

V = 1/3 × π·r²·h

Where;

V = The volume of the cone = 7.77 ft.³

r = The radius of the cone

h = The height of the cone = 4 ft.

By substituting the vales of 'h' and 'V' in the above equation, we have;

7.77 ft.³ = 1/3 × π × r² × 4 ft.

∴ r = √(3 × 7.77 ft.³/(π × 4 ft.)) = 1.36196580784 ft.

∴ The radius of the cone, r ≈ 1.4 ft. (rounding the answer to the nearest 10th)

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it