Ben uses a compass and a straightedge to construct ∠DEF ≅ ∠ABC, as shown below: The art shows two figures. The figure on the left shows two rays BA and BC with a common endpoint B. An arc drawn from B cuts the ray BA at H and the ray BC at I. The figure on the right shows two rays ED and EF with a common endpoint E. An arc drawn from E cuts the ray ED at J and the ray EF at K. Another arc drawn from K cuts the ray ED at J. Which statement best explains why Ben uses the width BI to create the arc JK from point E? ∠DEF ≅ ∠ABC when BH = EK, BI = JK, and HI = EJ.
BI = JK when ∠DEF ≅ ∠ABC.
BI = EJ when ∠DEF ≅ ∠ABC.
∠DEF ≅ ∠ABC when BH = EJ, BI = EK, and HI = JK.

Ben uses a compass and a straightedge to construct ∠DEF ≅ ∠ABC, as shown below: The art shows two figures. The figure on the left shows two rays BA and BC with a common endpoint B. An arc drawn from B cuts the ray BA at H and the ray BC at I. The figure on the right shows two rays ED and EF with a common endpoint E. An arc drawn from E cuts the ray ED at J and the ray EF at K. Another arc drawn from K cuts the ray ED at J. Which statement best explains why Ben uses the width BI to create the arc JK from point E?

∠DEF ≅ ∠ABC when BH = EK, BI = JK, and HI = EJ.

BI = JK when ∠DEF ≅ ∠ABC.

BI = EJ when ∠DEF ≅ ∠ABC.

∠DEF ≅ ∠ABC when BH = EJ, BI = EK, and HI = JK.

the answer is stop cheating on things stoopid

step-by-step explanation:

im eatin up the 44