A 133.5 kg crate, sliding on the floor, is brought to a stop by a 54.5 N force. What is the deceleration of the crate?

0.40m/s^2

Step-by-step explanation:

Given data

Mass= 133.5kg

Force F= 54.5N

The expression for the force acting is

F=ma

substitute

54.5=133.5*a

]Divide both sides by 133.5

a= 54.5/133.5

a= 0.40 m/s^2

Hence the acceleration is 0.40m/s^2

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (

-60.75

step-by-step explanation:

just add the numbers then put the negative sign on it