Maths very easy class 8​

Rs. 333

Step-by-step explanation:

Area of the surface of the cuboidal box to be painted = surface area of the cuboidal box - area of the base

✔️Surface area of the cuboidal box = 2(L*W + W*H + L*H)

L = 6 cm

W = 4 cm

H = 2.5 cm

Surface area of the cuboidal box = 2(6*4 + 4*2.5 + 6*2.5) = 2(24 + 10 + 15) = 2(49)

Surface area of cuboidal box = 98 cm²

✔️Area of base = L*W

= 6*4 = 24 cm²

Area of the cuboidal box to be painted = 98 - 24 = 74 cm²

✔️Cost of painting 74 cm² at Rs. 4.50 per cm² = 74 × 4.50 = Rs. 333

x+y=90

x=30-y=x

step-by-step explanation:

if you understand you will get the answer

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq