Find three consctive postive integers such that the prodect of the median integer and the largest integer is 72

7,8,9

Step-by-step explanation:

Let the numbers be a, a+1 and a+2. Therefore, based on the question, this will be:

= (a + 1)(a + 2) = 72

a² + 2a + a + 2 = 72

a² + 3a + 2 - 72 = a

a² + 3a - 70 = 0

a² + 10a - 7a - 70 = 0

a(a + 10) - 7(a + 10)

a - 7 = 0

a = 7

Since a = 7

a + 1 = 7+1 = 8

a + 2 = 7+2 = 9

The numbers are 7,8 and 9

answer: h

step-by-step explanation: