A sea lion swims in still water at the speed of 15 km/h. While hunting for fish, it swims with the current for 35 km and against the same current for 25 km. The sea lion swims with the current for the same amount of time it swims against the current. What is the speed of the current?

x = 5/2 km/h

Step-by-step explanation:

Lets x be the speed of the current

The sea lion's speed with the current: 15 + x

The sea lion's speed against the current: 15 - x

Total distance in km with the current: 35

Total distance in km against the current: 25

Time with the current: 35/(15 + x)

Time against the current: 25/(15 - x)

So we do...

35/(15 + x) - 25/(15 - x) = 0

35(15 - x)/(15 + x) - 25(15 + x)/(15 - x): Having common denominators which is (15 + x)(15 - x)

525 - 35x - 375 - 25x = 0: Mutipling the (15 + x)(15 - x)to 0 getting 0

150 - 60x = 0

30(5 - 2x) = 0

x = 5/2

2.5km/h

Step-by-step explanation:

We all in rsm?

the correct answer is the second option

77

step-by-step explanation: