An angle is 2/3 of its complement what is its magnitude

36°

Step-by-step explanation:

Two angles A and B are complementary if:

A + B = 90°.

In this case, we know that one angle is 2/3 of its complement.

Then we can write this as:

A = (2/3)*B

Now we can replace this in the equation ( A + B = 90°) and solve for B (remember that we want to find the value of A, the original angle):

(2/3)*B + B  =90°

(2/3)*B + (3/3)* = 90°

(5/3)*B = 90°

B = (3/5)*90° = 54°

And the other angle can be found with the equation (A = (2/3)*B)

then we get:

A = (2/3)*54° = 36°

The magnitude of the angle is 36°.

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.