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(8x4 + 5x3 + 4x2 - x + 7)/(x + 1)

For this problem, where the leading coefficient of the divisor is 1, plain 'ol long division will suffice here.

x + 1  |8x4 + 5x3 + 4x2 - x + 7

So x + 1 goes into the dividend how many times? Ask yourself, what do I need to multiply x by in order to get back an 8x4?  8x3. So multiply 8x3 by the divisor like you would in regular long division, except when you're finished change the signs of those two terms (to account for the fact that we are really doing a subtraction) and sum together.

        8x3

x + 1 |8x4 + 5x3 + 4x2 - x + 7

     (-)8x4 (-) 8x3

          0x4 - 3x3 + 4x2

Bring down the 4x2 term and repeat. What do I need to multiply x by in order to get negative 3x3? -3x2. Multiply by the divisor and change the signs (again, shown in parentheses) and sum.

        8x3 - 3x2_+ 7x_- 8

x + 1 |8x4 + 5x3 + 4x2 - x + 7

     (-)8x4 (-)8x3

         0x4 - 3x3 + 4x2

             (+)3x3 (+)3x2

                 0x3  + 7x2  - x

                        (-)7x2 (-)7x

                          0x2 - 8x + 7

                              (+)8x (+)8

                                    0x + 15

This gives a remainder of 15, and like regular long division, can be written over the divisor as 15 / (x + 1)

So the answer is 8x3 - 3x2 + 7x - 8 + (15/(x+1))

step-by-step explanation:

try remembering the steps

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.