The function g(x) = x2 – 10x + 24 is graphed on a coordinate plane. Where will the function cross the x-axis? (–6, 0) and (–4, 0) (–2, 0) and (–12, 0) (4, 0) and (6, 0) (12, 0) and (2, 0)

Solve x^2-10x+24 = 0
x = [10 ± √(10^2-4(1)(24))]/[2(1)] = 6,4
(6,0) and (4,0)

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm