Please help with either of these questions. Put the answer in the comments please

2) distance = 4 km

Displacement = 4 km east

3) distance = 35 km

Displacement = 5 km north

Step-by-step explanation:

2. He runs for 3 km in the east direction and then stops.. He now runs another 1 km in the same direction then stops.. Thus,

Total distance covered = 3 + 1 = 4 km

Total displacement is how far he is from his starting point = 3 + 1 = 4 km east

3) Runs 20km north and then runs 15 km back from starting point.

Thus;

Total distance covered = 20 + 15 = 35 km

Total displacement is distance from starting point = 20 - 15 = 5 km north

Subtracted because an opposite direction was taken after the 20km back to her starting point.

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.