Problem: ​Prove that the quadrilateral defined by the points F(6,4), R(1,3), O(3,2), G(−2,1) is a parallelogram. What Method/Formula(s) did you select?
(Please explain and show full work)

114 cm²

Step-by-step explanation:

Area of shaded region

= area of circle -area of square

\boxed{area \: of \: circle = \pi {r}^{2} }

areaofcircle=πr

2

Given that radius= 10cm, r= 10cm.

\boxed{area \: of \: square = side \: \times side}

areaofsquare=side×side

Let the length of a side of the square be x cm.

Applying Pythagoras Theorem,

10² +10²= x²

100 +100= x²

x²= 200

x = \sqrt{200}x=

200

Area of square

= x²

= 200cm²

Area of shaded region

= 3.14(10²) -200

= 3.14(100) -200

= 314 -200

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42